Nice trick.
On 6月13日, 上午9時36分, brian <bally.z...@gmail.com> wrote:
> On Fri, Jun 12, 2009 at 2:37 PM, amuhlou<amysch...@gmail.com> wrote:
>
> > putting it all together, you'd get something like:
>
> > $('#div1').replaceWith($('#div2')).remove();
>
> > first you find div1, then replace it with div2, then remove div1
>
> There's no need for remove() because it will have been replaced already.
