On Jun 28, 5:19 am, Laszlo Bagi <laszlo.b...@gmail.com> wrote:
> Hi!
>
> I've started to deal with jQuery for few months ago and I bumped into
> some freaks but this was the first time (yesterday) when I blunder
> into a problem which queries the availability of the whole jQuery
> framework.
>
> I've got several problems with the remove() function... I hope you can
> help me to solve them.
>
> According to the documentation:
>
> jQuery.remove():
> Removes all matched elements from the DOM.
> This does NOT remove them from the jQuery object, allowing you to
> use the matched elements further.
>
> So if I understand the documantation well:
>
> 1) There is a given window "window1". I try to open an other window
> "window2" FROM "window1" and I try to move an HTML element from
> "window1" to "window2". Is that possible that the element belonging to
> deleted jQuery object will be able to available in both JQuery
> "array"?
What do you mean "jQuery array"? Everytime you call $/jQuery you
create a new object, there is no global jQuery object containing
elements. When you remove an element, it is detached from the DOM and
saved in a specific object.
var myElement = $('#myEl').remove();
// #myEl is now in the myElement object, detached from any document
// you can append it to another window's document
$(window2.document.body).append( myElement );
(not sure the appending will work, there are issues when dealing with
HTMLElements across frames you have to take into account, but that's
the logic)
>
> 2) If I have to generate a list of unique "id"-s which contains
> several hundred rows then the jQuery "array" is just growing, growing,
> growing ad infinitum?
Why would you do that? And what do you mean by "the jQuery array"
again? No, an object will grow as large as the number of elements you
put in it.
