[jQuery] Re: G is undefined

[expresso]

I understand.  Thanks for the explanation.

On Jun 29, 12:19 pm, "Michael Geary" <m...@mg.to> wrote:
> That's right, your JSON is perfectly valid. You can test it at:
>
> www.jsonlint.org
>
> Here's the formatted output from that site, with the image tags elided for
> clarity, and comments added showing how you'd access each part of it
> directly in JavaScript:
>
>     // Data
>     [
>         // Data[0]
>         {
>             // Data[0].ImageTag
>             "ImageTag": "..."
>         },
>         // Data[1]
>         {
>             // Data[1].ImageTag
>             "ImageTag": "..."
>         }
>     ]
>
> As you can see, what you have is an array of two elements. Each of those
> elements is an object with a single property named ImageTag with a string
> value.
>
> Now back to your code. This is where it goes wrong:
>
> $.each(Data.items, function(i, item) {...});
>
> "Data" here is the JSON data, and you're trying to get its "items" property
> and use it as an array. But there is no "items" property - Data itself is
> the array, so you'd use it directly:
>
> $.each(Data, function(i, item) {...});
>
> JSON that would work with your original code using Data.items would look
> like this:
>
>     // Data
>     {
>         // Data.items
>         "items": [
>             // Data.items[0]
>             {
>                 // Data.items[0].ImageTag
>                 "ImageTag": "..."
>             },
>             // Data.items[1]
>             {
>                 // Data.items[1].ImageTag
>                 "ImageTag": "..."
>             }
>         ]
>     }
>
> BTW, I suggest using variable names that begin with lower case. The upper
> case first letter makes people think it's the name of a constructor.
>
> -Mike
>
> > From: expresso
>
> > some tells me that my original JSON is totally valid with the [ and ]
>
> > On Jun 29, 11:03 am, MorningZ <morni...@gmail.com> wrote:
> > >http://en.wikipedia.org/wiki/JSON
>
> > > will show you what it should look like... notice the
> > outside symbols
> > > are { ... }, not [ .... ]
>
> > > again, you should look at this if you are working with .NET
> > and JSON,
> > > it really takes all this guess work from the equation:
>
> > >http://james.newtonking.com/pages/json-net.aspx
>
> > > On Jun 29, 12:01 pm, expresso <dschin...@gmail.com> wrote:
>
> > > > Ok, so what should it be wrapped in or how should I reformat this?
>
> > > > On Jun 29, 10:58 am, MorningZ <morni...@gmail.com> wrote:
>
> > > > > Wow, is posting the same thing every 3 mins to bump your topic
> > > > > annoying....
>
> > > > > Anyways,
>
> > > > > your results wrapped in [ .... ] signifies an Array, not a JSON
> > > > > object....  hence ".getJSON" has no idea what to do with it
>
> > > > > On Jun 29, 11:53 am, expresso <dschin...@gmail.com> wrote:
>
> > > > > > So is this valid JSON that jQuery can parse? or do I need an
> > > > > > initial level such as "Images":
>
> > > > > > [{"Images" :
> > > > > > [{"ImageTag":"&lt;img
> > src=&quot;http://www.xxx.com/image/473.jpg";
> > > > > > alt=&quot;&quot;&gt;"},{"ImageTag":"&lt;img
> > > > > > src=&quot;http://www.xxx.com/image/4852.jpg";
> > > > > > alt=&quot;&quot;&gt;"} ]]
>
> > > > > > On Jun 29, 10:37 am, expresso <dschin...@gmail.com> wrote:
>
> > > > > > > Ok, figured out that data.items is undefined. Not sure why
> > > > > > > because here's the json my url returns:
>
> > > > > > > [{"ImageTag":"&lt;img
> > src=&quot;http://www.xxx.com/image/473.jpg";
> > > > > > > alt=&quot;&quot;&gt;"},{"ImageTag":"&lt;img
>
> > src=&quot;http://www.xxx.com/image/4852.jpg"alt=&quot;&quot;&g
> > > > > > > t;"}]
>
> > > > > > > On Jun 29, 10:33 am, expresso <dschin...@gmail.com> wrote:
>
> > > > > > > > I get the following error:
>
> > > > > > > > G is undefined
> > > > > > > > init()()jquery-1....2.min.js (line 12)
> > (?)()()Carousel.aspx
> > > > > > > > (line 30) I()jquery-1....2.min.js (line 19)
> > > > > > > > F()()jquery-1....2.min.js (line 19) [Break on this error]
> > > > > > > > (function(){var l=this,g,y=l.jQuery,p=l.....each
> > > > > > > > (function(){o.dequeue(this,E)})}});
>
> > > > > > > > in jquery-1.3.2.min.js
>
> > > > > > > > when I call this method of mine:
>
> > > > > > > >     $.getJSON("http://localhost:59396/xxx/xxxHandler.ashx?
> > > > > > > > action=xxxjson",
> > > > > > > >         function(Data) {
> > > > > > > >         $.each(Data.items, function(i, item) {
> > > > > > > >         alert('got here');
> > > > > > > >         carousel.add(i,
> > > > > > > > mycarousel_decodeEntities(item.ImageTag));
> > > > > > > >                 if (i == 3) return false;
> > > > > > > >             });
> > > > > > > >         });
>
> > > > > > > > I know I can get inside function(Data){ and that
> > the error
> > > > > > > > starts at $.each I believe