This one is more general (and faster, I think: no if-else, no regexp)
Number.prototype.padRight = function (fill) {
var v = this.toString().split('.'), d = v[1] || '';
return (v[0] || '0') + '.' + d + fill.substr(d.length);
}
test1 = 2;
test2 = 3.141592;
test3 = 0.001;
test4 = .33;
test1.padRight('0000000000'); // returns 2.0000000000
test2.padRight('000000'); // returns 3.141592
test3.padRight('00'); // returns 0.001
test4.padRight('0000000000'); // returns 0.3300000000
As I see you're dealing with cents, money and stuff, I have to
remember you that JavaScript use IEEE 754 Floating Points as its own
internal number type, so 0.1 + 0.2 !== 0.3: people tend to be very
picky when dealing with money, especially if it's *their* money! :)
So: be careful. And if you're relying on JavaScript logic to handle
people's money, change programming language, JavaScript is not good at
it.
On Tue, Jul 7, 2009 at 12:11, weidc<mueller.juli...@googlemail.com> wrote:
>
> hi,
>
> thats my code:
>
> endpreis =Math.round(endpreis*100)/100;
>
> to round the price of something but i'd like to have 2,00 or 2,50
> instead of 2 and 2,5.
>
>
> i'd be happy about any help.
>
> --weidc
--
Massimo Lombardo
Linux user #437712
