Try:
$('.start-here li').filter(':has(ul)').append('<span class="ui-icon ui-
icon-plus"></span>');
-Dan
On Wed, Aug 5, 2009 at 11:59 AM, Panman <rpann...@gmail.com> wrote:
>
> I have selected a list that contains sub-lists. Now, I'd like to
> search for the list items that contain sub-lists (but not including
> the sub-list-items). I think the example below will explain what I'm
> trying to do.
>
> HTML:
> <ul class="start-here">
> <li>Do Not Need</li>
> <li>NEED THIS ITEM
> <ul>
> <li>Do Not Need</li>
> <li>Do Not Need</li>
> </ul>
> </li>
> <li>Do Not Need</li>
> <li>NEED THIS ITEM
> <ul>
> <li>Do Not Need</li>
> <li>Do Not Need</li>
> <li>NEED THIS ITEM
> <ul>
> <li>Do Not Need</li>
> <li>Do Not Need</li>
> </ul>
> </li>
> <li>Do Not Need</li>
> </ul>
> </li>
> <li>Do Not Need</li>
> </ul>
>
> jQuery:
> $('.start-here li').filter(':has(li)').append('<span class="ui-icon ui-
> icon-plus"></span>');
>
> The above jQuery statement selects the correct <li> but also all child
> <li>'s, which I do not want.
>
