Hmm. Would this be expected to work?
$gallery.find('li[title='+$title_to_searchl+']').css('color','red');
On Aug 28, 1:31 pm, tatlar <robertlnew...@gmail.com> wrote:
> Oops. This sentence:
> "I want to traverse the array, looking at the title attribute, and if
> it is in the array $search I want the style changed. "
> Should be:
> "I want to traverse the list, looking at the title attribute, and if
> it is in the array $search I want the style changed."
>
> And this:
>
> var $title_to_search = value;
> // pseudo code.... I know this is junk
> $gallery.find('li').attr('title',$title).css('background-
> color','red');
>
> Should be:
> var $title_to_search = value;
> // pseudo code.... I know this is junk
> $gallery.find('li').attr('title',$title_to_search).css('background-
> color','red');
>
> On Aug 28, 1:27 pm, tatlar <robertlnew...@gmail.com> wrote:
>
>
>
> > i think this is a pretty simple question, but i can't seem to figure
> > it out.
>
> > i have a list in a div:
>
> > <div id="gallery">
> > <ul>
> > <li title="foo">foo</li>
> > <li title="bar">bar</li>
> > <li title="unicorn">unicorn</li>
> > </ul>
> > </div>
>
> > I have an array with values in it:
>
> > var $search = [ "foo", "bar" ] ;
>
> > I want to traverse the array, looking at the title attribute, and if
> > it is in the array $search I want the style changed.
> > Note that #gallery has about 450 list items - the one above is
> > abridged for this post.
> > The array $search will at most have 5 items.
>
> > So, is it faster to do a $.each() on the list items, or do a $.each()
> > on the $search items. I am pretty sure it is faster to do the latter,
> > but I am not sure how to get the title attribute from the list items
> > for the match.
>
> > Something like?
>
> > $.each( $search, function(i, value) {
> > var $title_to_search = value;
> > // pseudo code.... I know this is junk
> > $gallery.find('li').attr('title',$title).css('background-
> > color','red');
>
> > });
>
> > Can someone refine this for me? Thanks in advance.
