[jQuery] Re: An idiot's question about returning results from a form submission

[Alan]

Thank you, once again, Brian.

I got everything working by replacing...
        $('#imageUploader1').ajaxForm(function() {
                alert("I wish I could post the actual server response.");
        });

with...
        var options = {success: showResponse};
        $('#imageUploader1').ajaxForm(options);


and then added an additional function...
        function showResponse (responseText, statusText){
                alert("The response from the server is:" + responseText);
        }

Now, I can substitute the alert for code that will update the photo on
the web page.

Thanks again.