In your first example, you're trying to call a .queue() method on the return value from $.getJSON(). $.getJSON() returns either an XMLHttpRequest object or nothing. It doesn't return the $ object.
Also, $getJSON() returns *before* the request is completed. In the second example, you're trying to call a .queue() method on the return value from $.each(). $.each() returns the object you passed in as its first argument. So you're calling data.queue() which doesn't exist. Instead of chaining your calls, you can just make them separate statements: $.getJSON( "http://....";, function(data) { $.each( data, function(i, item) { //... }); $.queue(function() { $("#div").fadeIn(); }); }); I must confess I've never used $.queue(), so I don't know if that code is correct, but at least you wouldn't get the undefined queue method. But are you simply trying to fade in your div after the $.getJSON() request is completed and after you run the $.each() loop? You don't need queue for this: $.getJSON( "http://....";, function(data) { $.each( data, function(i, item) { //... }); $("#div").fadeIn(); }); -Mike On Sun, Sep 20, 2009 at 11:28 AM, cerberos <pe...@whywouldwe.com> wrote: > > I'm trying to queue to start once a getJSON request has finished but > it's not working, I'm getting '...queue is not a function'. > > I've tried > > $.getJSON("http://....";, function (data){ > $.each(data, function(i,item){ > ... > }); > }).queue(function(){ > $("#div").fadeIn(); > }); > > and > > $.getJSON("http://....";, function (data){ > $.each(data, function(i,item){ > ... > }).queue(function(){ > $("#div").fadeIn(); > }); > }); > > > but I get the same error. I've tried with 1.3.2 and 1.2.6. >
