$('p[id=' + myClr + ']').addClass('bold');
you need to concatenate the variable in with the literal text so it can be
evaluated.
On Tue, Sep 29, 2009 at 10:59 AM, roi <roi.agn...@gmail.com> wrote:
>
> I am trying to do something that seems very simple, but can not get to
> work! Basically, I want to find an element whose ID equals a certain
> value, as represented by a variable. The variable is derived from a
> dropdown list. Here is my code:
>
> $(document).ready(function(){
> $("select").change(function() {
> var myClr = $("select").val();
>
> $("p[id=myClr]").addClass("bold"); //this is the line giving me
> trouble
> });
> });
>
> I am wondering if it is legal to use a variable within the filter - if
> I replace it with an actual ID value it works fine, but when I
> substitute the variable name nothing happens.
>
> I am sure I am doing something dumb! Thanks for any suggestions.
>
> Roi
>
--
Charlie Griefer
http://charlie.griefer.com/
I have failed as much as I have succeeded. But I love my life. I love my
wife. And I wish you my kind of success.
