$(".widget > .widget") // stops at first desendant
$(".widget .widget : first") //might work too, haven't tried it
Andrew Ingram wrote:
Apologies for the subject line, I'm struggling to explain the problem
in a concise manner.
I have the following document:
<body>
<h1 class="page-editable" widget="line">Page Title Goes Here</h1>
<div widget="repeat-area">
<div widget="repeat">
<h2 widget="line">Section Heading</h2>
<div widget="repeat-area">
<div widget="repeat">
<h3 widget="line">Section Title</h3>
<p widget="textarea">Content…</p>
<img src="" widget="image" />
</div>
<div widget="repeat">
<h3 widget="line">Section Title</h3>
<p widget="textarea">Content…</p>
<img src="" widget="image" />
</div>
</div>
</div>
</div>
</body>
I am trying to recursively access each element with the attribute
'widget'. The first level of recursion is easy:
$('[widget]:not([widget] [widget])')
Which matches all widgets that are not descendants of other widgets,
ie the top level.
The problem is with the next recursive steps, I can't figure out how
to find just the first level of widgets that are a descendents of the
current node.
$('[widget]:not([widget] [widget])').each(function(i){
// For example, I need a query I'd put here to access the next
level of elements.
});
There is no guarantee that the widgets would be direct children of
each other, or that they'd be on the same tree level as their
'sibling' widgets.
Basically I need a way of finding all widgets that are descendents of
the current working node, but with no other widgets in-between.
If anything needs clarifying let me know.
Regards,
Andrew Ingram
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