Sorr, I made mistake, there are two wrong coding No.1, onclick="doCopy()" No.2, $("#user2_name").val($("#user1_name").val())
> $("#user2_pass").val($("#user1_pass").val()) On Tue, Oct 20, 2009 at 10:28 AM, ReynierPM <rper...@uci.cu> wrote: > > Bi Jing wrote: > >> HTML code: >> >> <input type="checkBox" onclick="doCopy"/>Copy >> >> <form id="user1"> >> <input type=text id=user1_name /> >> <input type=text id=user1_pass /> >> </form> >> >> <form id="user2"> >> <input type=text id=user2_name /> >> <input type=text id=user2_pass /> >> </form> >> >> >> JS code: >> >> function doCopy(){ >> $("user2_name").val($("user1_name").val()) >> $("user2_pass").val($("user1_pass").val()) >> } >> >> > Isn't working. > > HTML Code: > <label for="same" class="first">Same <input type="checkbox" name="same" > id="same" onclick="doCopy" /></label> > > <label for="first_name" class="first">First Name: <input type="text" > name="first_name" id="first_name" value="" size="" /></label> > <label for="first_name1">Middle Name: <input type="text" name="first_name1" > id="first_name1" value="" size="" /></label> > > JS Code: > function doCopy(){ > $("first_name1").val($("first_name").val()) > } > Where is the error? > -- > Saludos > ReynierPM >