What about index_news = index_news + 3 ? hth
Rick -----Original Message----- From: jquery-en@googlegroups.com [mailto:jquery...@googlegroups.com] On Behalf Of deep Sent: Monday, October 26, 2009 9:40 AM To: jQuery (English) Subject: [jQuery] Re: take 3 values at time for fade in fade out effect. I have tried something like this index_news +=3; but its not working. can anyone please help me how can i increase my index_new value by 3? On Oct 26, 5:07 pm, deep <deeps...@gmail.com> wrote: > Hello > > I have following code which i am using for fade in fade out effect. > with this code at time only one image is coming. I want at time it > should show 3 images. like 1,2,3 then 4,5,6 > > Here is my code. > > var index_news = 0; > > // > > function initNews() { > > $('div#feed-ticker') > > .slideDown('slow', > > function() { > > $('div#feed-ticker li').eq( index_news ).fadeIn(); > > setTimeout( next_news, 5000 ); > > } > > ); > > } > > function next_news() { > > $('div#feed-ticker li') > > .eq( index_news ) > > .fadeOut(1000, > > function() { > > index_news++; > > if( index_news> $('div#feed-ticker li').length-1 ) > index_news = 0; > > $('div#feed-ticker li').eq( index_news ).fadeIn(); > > setTimeout( next_news, 5000 ); > > } > > ); > > } > > Can anyone tell me how can i set the value here. May be because of > this index_news++; its taking one value at time. but how can i > increase it by 3? > > Thanks in advance.
