Thx!!!  This is exactly what i was looking for!!!   I knew there was a
simple solution.

Joe C

On Oct 27, 11:08 am, Michel Belleville <michel.bellevi...@gmail.com>
wrote:
> Well, you're using $.ajax() and the context of its callbacks make this the
> xhr object, so no surprise there.
>
> This should work as you expect :
>
> var myself = this;
> var Zone = function(data) {
> myself.someInfo = data;
> myself.load = Zone_Load;};
>
> var Zone_Load = function() {
> $.ajax({
> type: "GET",
> url: "http://localhost/foo.xml";,
> success: requestSuccess});
> };
>
> var requestSuccess = function(data) {
> myself.someInfo = $(data).find('type');
>
> };
>
> JavaScript allows methods to access all objects contained by the context
> they're declared in (provided you don't declare nested variables overriding
> existing context variables). In this case we declare "myself" and give it a
> reference to the content of "this" so when this is bound to other objects we
> still can use "myself" to access the desired object.
>
> Michel Belleville
>
> 2009/10/27 Joe <joecel...@gmail.com>
>
>
>
> > I am trying to access my own JS object from within an ajax call, and
> > can't figure out how to get it to work.   Whenever I access "this" in
> > the function, it returns the ajax context and not my JS object
> > context.  My code looks something like this.  I have a Zone object
> > defined in a JS file like this:
>
> > //====================START CODE================
> > function Zone(data){
> >   this.someInfo = data;
> >   this.load = Zone_Load;
> > }
>
> > function Zone_Load(){
> >        $.ajax({
> >           type: "GET",
> >           url: "http://localhost/foo.xml";,
> >                success: requestSuccess
> >         });
> > }
>
> > function requestSuccess(data){
> >  this.someInfo = $(data).find('type');
> > }
> > //====================ENDCODE================
>
> > I am having problems with the last line.  How do i get access to the
> > JS object, so that i can set some info on it, based on the ajax call?
>
> > Any help would be appreciated?
>
> > thx,
>
> > Joe C

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