well,
I ll be more specific, here is the code part
**
$("#image_overlay_group_form").ajaxForm({
success: function(msg) {
var downLat = $("#image_overlay_sw_lat").val();
var downLon = $("#image_overlay_sw_lng").val();
var upLat = $("#image_overlay_ne_lat").val();
var upLon = $("#image_overlay_ne_lng").val();
var fileName = $("#image_overlay_file").val();
alert("rs image filename: " + fileName + " , " + upLon
+ ", "+ downLat); // --> this has empty values!!
$("#" + project_name + "_" + layer_name +"_"+
group_name+ "_new_legend_feature_entry_point").after(msg);
},
resetForm: true // Reset the form after a successful AJAX
call
});
**
my guess is that the form inputs are emptied somehow and thus no
values are available...but in some other ajaxForms i have, i use the
same technique and it works..
I ll keep trying but any suggestions are much appreciated!
On Oct 30, 7:29 pm, James <james.gp....@gmail.com> wrote:
> The .val() should work. I've tried it and it works on FF3.5, IE6+,
> Safari and Chrome (all WinXP).
> The only differences I found is that FF, Safari, Chrome returns just
> the filename, whereas IE6+7 returns the full path of the user file
> (privacy issue), and IE8 uses 'C:\fakepath' as the directory
> (misleading..).
>
> On Oct 30, 8:29 am, Adonis <achrysoch...@hotmail.com> wrote:
>
> > hi,
>
> > I was wondering if anyone knows a way togetthe file name(the one the
> > user has just browsed and is about to upload using the form) from a
> > forminput.
> > I tried $("#fileInput").val() but it does not work.
>
> > cheers,
