Nevermind. My original approach worked. I had just forgotten to use th tags
instead of td tags in the thead section of the table in my AJAX call. Silly
mistake.
aquaone wrote:
>
> try:
> $('#mainContent').html(data).find('#ratesTable').tablesorter();
>
>
>
> On Mon, Nov 9, 2009 at 20:38, sumdog <sum.not...@gmail.com> wrote:
>
>>
>> Hey there,
>>
>> I've read through several AJAX+tablesorter posts and am still a little
>> confuzzled on this. I am loading an entire table into a div like so:
>>
>> <div id="mainContent">
>> <p>Loading...</p>
>> </div>
>>
>> <script type="text/javascript">
>> $(document).ready( function() {
>> $.get('/ajaxRates',{},
>> function(data) {
>> $('#mainContent').html(data);
>> $('#ratesTable').tablesorter();
>> });
>> });
>> </script>
>>
>> The /ajaxRates URL returns the HTML table. I place it into the div using
>> the
>> function right after it. I then call that new table and apply
>> tablesorter()
>> to it. If I do this to an inplace table, it works fine. It's just the
>> AJAX
>> table I'm having trouble with.
>>
>> The new table should be fully in the DOM by the time that function
>> returns
>> correct? Is there some other event I need to wait for or attach somehow
>> in
>> order to get this to work correctly?
>>
>> Thanks
>> Sumit Khanna
>> http://penguindreams.org
>> --
>> View this message in context:
>> http://old.nabble.com/tablesorter-%2B-AJAX-tp26278194s27240p26278194.html
>> Sent from the jQuery General Discussion mailing list archive at
>> Nabble.com.
>>
>>
>
>
--
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Sent from the jQuery General Discussion mailing list archive at Nabble.com.
