Thank you Richard.
But what about to to use the example with only the first 3 '$
('div.star-rating.rater-0.auto-submit-star.star-rating-applied.star-
rating-live')' in page.
Is that i need to show the results of the rating.
if the result is 3 then add the class to only the first 3 stars.
On 2 dez, 03:21, "Richard D. Worth" <rdwo...@gmail.com> wrote:
> On Tue, Dec 1, 2009 at 9:53 PM, led <l.r....@sapo.pt> wrote:
> > I'm try to use star rating plugin frm
> >http://fyneworks.com/jquery/star-rating/.
>
> > I need to add class 'star-rating-on' on the divs with class 'star-
> > rating rater-0 auto-submit-star star-rating-applied star-rating-
> > live' .
>
> That's not a class, it's five classes. Spaces in a class attribute value
> separate multiple class names.
>
>
>
> > I can use:
>
> > $("div.star-rating rater-0 auto-submit-star star-rating-applied star-
> > rating-live")
>
> that selector is looking for all elements of type star-rating-live within an
> element of type star-rating-applied within an element of type
> auto-submit-star within an element of type rater-0 within an element of type
> div with a class of star-rating. In this case the space acts as a descendant
> selector. That would only do if your markup looked something like this
>
> <div class="star-rating">
> <rater-0>
> <auto-submit-star>
> <star-rating-applied>
> <star-rating-live>
> </star-rating-live>
> </star-rating-applied>
> </auto-submit-star>
> </rater-0>
> </div>
>
> and it would match the star-rating-live element, not the div.
>
> > .each(function(){
> > $(this).addClass('star-rating-
> > on')
> > });
> > but it isn't working.
>
> If you really only want the divs with all those classes:
>
> $('div.star-rating').filter('.rater-0').filter('.auto-submit-star').filter('.star-rating-applied').filter('.star-rating-live').addClass('star-rating-on');
>
> or more succinctly:
>
> $('div.star-rating.rater-0.auto-submit-star.star-rating-applied.star-rating-live').addClass('star-rating-on');
>
> - Richard
