try to use an associative array to build the menu
php:
get data from a yaml file or txt or whatever.
then build the array structure and encode to json. Also could make the file
directly in json format
$menu array("link1" => "http://xxxx";, "link2" => array ( "link2.1" =>
"http:/....", "link2.2" => "http://.."; ) )
echo json_encode($menu);
jquery:
var mymenu;
$.ajax({
async: false,
success: function(data) { mymenu = data; (render the menu) },
url: "http://urltomenufile.php";,
type: "get",
dataType: "json"
});
Thats all
--
Carlos De Oliveira
Departamento De Sistemas
Consultor Senior
0426 517 73 01
0212 204 69 60
cdeolive...@grupozoom.com
card...@gmail.com
