start: function(e, ui) { $(ui.placeholder).append(ui.item.clone().find
("tr:first").each(function() { $(this).find("td").each(function() { $
(this).empty()}) })); },On Jan 6, 12:24 pm, justicfu <[email protected]> wrote: > add this will be solve the helper problem: > helper: function(e, ui) { return $("<table></table>").addClass > ("helper").append(ui.contents().clone()); } > > But how to solve the placeholder problem? --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "jQuery UI" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/jquery-ui?hl=en -~----------~----~----~----~------~----~------~--~---
