If they all share a common container, you could call .selectable() on that and specify a filter that matches all the child items. - Richard
On Tue, Aug 4, 2009 at 11:39 AM, Jaggi <[email protected]> wrote: > > Hi Paul, > > I've had a few issues disecting this, mainly how to get it to work > without the draggable. I want to be able to select all the blocks > which may span multiple child elements and be able to select them > all. > > E.g. > > <div> > <ul>....<ul> > <ul>....<ul> > </div> > > the UL's might be side by side so i would want to select the first one > on the left and be able to drag all the way across to the second one > in the right. If not i would like to able to do this using a table > e.g. select all the td elements by dragging across. I'm wondering if > any of this is possible? > > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "jQuery UI" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/jquery-ui?hl=en -~----------~----~----~----~------~----~------~--~---
