You don't need the $() you can just have ui.draggable.val(). It really depends on what you're dragging to use val()... If you're trying to debug try utilizing firefox and firebug with something like console.log(ui.draggable). Your value really shouldn't change, only its position unless you have some logic in there that changes its value.
------------------------------------------------- Brandon Ryall Software Developer eMaint Enterprises LLC 438 N. Elmwood Road, Suite 201 Marlton, NJ 08053 P 856-810-2700 x7180 F 253-323-6353 On Fri, Oct 9, 2009 at 3:55 PM, marcucio <[email protected]> wrote: > > $(ui.draggable).value() > > On Oct 7, 1:49 pm, Andrew <[email protected]> wrote: > > Hi there > > > > Is it possible to get the value of draggable once it has been dropped? > > > > Many thanks > > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "jQuery UI" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/jquery-ui?hl=en -~----------~----~----~----~------~----~------~--~---
