Please create a bug ticket for this here: http://dev.jqueryui.com/newticket (note: requires registration)
Thanks. - Richard On Sun, Oct 18, 2009 at 5:06 AM, [email protected] < [email protected]> wrote: > > hi, > Please visist http://jsbin.com/aqaka/edit , then the > problem will appear. > The key point is that the 2 DIVs set to be droppable are > overlapping,then the event of Dropping is triggered twice. > > > On Oct 12, 3:59 pm, "[email protected]" > <[email protected]> wrote: > > hi, > > There are a couple of "DIV" ,one is on the top and the other is > > below it. Let's call the top one TOP,and the below one BELOW. > > Now the TOP contains many sub-DIV set to "float:right" that make > > the TOP "overflow",so some sub-DIV are hidden into the back of BELOW. > > Both sub-DIV and BELOW are set droppable for the pictures in > > them,and both of them have set action fordropevent, for example > > "alert('hello')"; of course, the pictures are draggable. > > Now the problem comes while dragging picture from sub-DIV in TOP > > to BELOW. If the area where the pictrue drops is just where the sub- > > DIV hides,thedropevent is triggered twice,that is 'hello' alert > > twice. And the picture factly drops into the sub-DIV ,not BELOW that I > > expected. > > I want the picture drops into the BELOW ,but it drops into the sub- > > DIV;I want the event set in BELOW is triggered,but both event of > > BELOW and sub-DIV are triggered. How to resolve the problem,thanks. > > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "jQuery UI" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/jquery-ui?hl=en -~----------~----~----~----~------~----~------~--~---
