Hi phicarre, At first sight, there seems nothing wrong with the script in your first example. I ran it at my pc and get no error. Your second example will not work, since you open the href-string with double-qoutes, and use them again around $name. You can only use single-qoute within the string (or double-quotes if you use single-quotes around the string).
Try writing your $output script on one line: $output .= "<div style='width:150px;'><a href=\"javascript:choice1 ($id,'$name')\">"; and see what happens. Is there a place where we can see your script? Edwin On Nov 8, 7:05 pm, phicarre <[email protected]> wrote: > From client side (javascript + jquery) the calling function is: > > function displayMember(code,idr) > { > var getVars = "code=" + code + "&id=" + idr; > $.ajax( > { > type: "POST", > url:'displayMember.php', > dataType: 'script', > data: getVars, > success: function(resultat) {}, > error: function(requete,iderror) {alert(iderror);} > }) > } > > Server side, php language, the displayMember.php builds a string > ($output) with data from a database. > $output is HTML code. Its a set of data inserted in a grid. > When a user clicks on a field, the javascript function choice1 is > executed. > > On 8 nov, 02:54, intrader <[email protected]> wrote: > > > Sorry, premature send. > > 1. It is not clear to me what choice1 is > > 2. It is not clear to me what $output is and where it is being issued > > (server or client) > > 3. Please provide your script for your choice1 function > > 4. Please provide yourAJAXcode including the callback funtion. > > 5. Please provide the server code and what language it is in. > > Thanks > > > On Nov 7, 8:56 am, intrader <[email protected]> wrote: > > > > It is not clear how you are calling the server, or whatajax > > > formulation you are using. Perhaps lack of encoding is theproblem. > > > > On Nov 7, 3:19 am, phicarre <[email protected]> wrote: > > > > > Hi all, > > > > >Problemwith .ajaxwith type = POST > > > > > error: missing ) after argument list > > > > > $output .= "<div style='width:150px;' ><a href=\"javascript:choice1 > > > > ($id,"; > > > > $output .= "'" . $name . "'"; > > > > $output .= ")\">"; > > > > > same error with > > > > > $output .= "<div style='width:150px;' ><a href=\"javascript:choice1 > > > > ($id,"; > > > > $output .= "\"" . $name . "\""; > > > > $output .= ")\">"; > > > > > no error but display choice1(99, instead of choice1(99,"10") > > > > > $output .= "<div style='width:150px;' ><a href='javascript:choice1 > > > > ($id,"; > > > > $output .= "'" . $name . "'"; > > > > $output .= ")'>"; > > > > > The calling function declares dataType as script > > > > > What is the correct formulation ? -- You received this message because you are subscribed to the Google Groups "jQuery UI" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/jquery-ui?hl=en.
