Function call — which `foo()` an `nsui()` are — has little to do with
`Function.prototype.call`. Function call (such as `foo()`) delegates to
internal [[Call]] method of whatever object you're invoking. In case of
`foo()` it's [[Call]] of `foo` function object. Unless the implementation
you're working with allows you to tap into this internal [[Call]] method
(and intersect it) overwriting `Function.prototype.call/apply` certainly
won't help here.
I don't think I've seen any implementations that expose [[Call]] to
user-level code.
--
kangax
On Thu, Mar 24, 2011 at 4:44 AM, Marc Palau <m...@palaueb.com> wrote:
> Hi everybody!
>
> -Just for Firefox- I'm trying to modify the Function object to output by
> console the execution flux of my application, I know firebug can capture for
> me that, but I want to modify the Function to play aroud with it.
>
> My approach is this, but it doesn't work (of course).
>
> Function.prototype._call = Function.prototype.call;
>
> Function.prototype.call = function(args){
> console.log(this);
>
>
> Function.prototype._call.apply(args,Array.prototype.slice._call(arguments,1));
> }
>
>
> function foo(){
> return 42;
> }
>
>
> var nsui = function(){
> return 42;
> }
>
> foo();
> nsui();
>
> //none happens :P
>
> Thanks in advance!
> marc
>
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