I am having a problem understanding how to run servlets. The Java Tutorial says the following: http://machine-name:port/servlet/servlet-name For example, the servlet that delivers the main page of Duke's Bookstore has the property servlet.bookstore.code=BookStoreServlet. To see the main page of the example, type the following URL into your browser: http://localhost:8080/servlet/bookstore Per my understanding, I should set the code property in the servlets.properties file as follows: servlet.bookstore.code=BookStoreServlet Then I should be able to type the location in a browser as follows: http://localhost:8080/servlet/bookstore I have had no success with this. I believe it is because of the start location which is set in the webserver.xml which is called when I invoke startserver.bat The start server is located in at g:/jswdk-1.0/ directory. Where do I put my Duke's Bookstore files in relationship to the startserver.bat file? I believe I need to change this line of code in the webserver.xml but I do not understand how this works even after reading the directions located in the same file. <WebApplication id="examples" mapping="/examples" docBase="examples"/> Any advice or direction to another source of information that will explain the webserver.xml file in a different way would be appreciated. John =========================================================================== To unsubscribe: mailto [EMAIL PROTECTED] with body: "signoff JSP-INTEREST". FAQs on JSP can be found at: http://java.sun.com/products/jsp/faq.html http://www.esperanto.org.nz/jsp/jspfaq.html
