Is this the actual code you tested and got the output ...
or
instead of the line String a = "aa";
you had some other code ??

actually, String a = "aa"; even if you loop does nothing ...

I think both the for loop will not be executed at all ...

the JVM should optimises the code ...
and the time should be same ...

BTW your second code snippet should be faster than the first one ...


----- Original Message -----
From: "ShriKant Vashishtha" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Friday, December 14, 2001 5:14 AM
Subject: Re: OffBeat question...Java performance.


> Hi,
>
> I apologise for the mistake. You are right. Please find the currect
> snippets.
>
>         String [] arrayStr = new String[20000];
>         System.out.println(System.currentTimeMillis());
>         for(i=0;i<arrayStr.length;i++){
>                     String a="aa";
>         }
>         System.out.println(System.currentTimeMillis());
>
> Output:
> 1008319728796
> 1008319728799
>
>         String [] arrayStr = new String[20000];
>         int length = arrayStr.length;
>         System.out.println(System.currentTimeMillis());
>         for(i=0;i<length;i++){
>             String a="aa";
>         }
>         System.out.println(System.currentTimeMillis());
>
> Output:
> 1008319767200
> 1008319767221
>
> Regards,
> -ShriKant
>
> A mailing list about Java Server Pages specification and reference wrote:
>
> > From: Sujit <[EMAIL PROTECTED]>@JAVA.SUN.COM on 12/14/2001 04:51 AM
EST
> >
> > Please respond to A mailing list about Java Server Pages specification
> and
> >       reference <[EMAIL PROTECTED]>
> >
> > To:   [EMAIL PROTECTED]
> > cc:
> > Subject:  Re: OffBeat question...Java performance.
> >
> > what is the difference between both the code ..
> >
> > I don't see any difference between the code
> > that is embedded between the system.out's
> >
> > am I missing something ??
> >
> > ----- Original Message -----
> > From: "ShriKant Vashishtha" <[EMAIL PROTECTED]>
> > To: <[EMAIL PROTECTED]>
> > Sent: Friday, December 14, 2001 4:34 AM
> > Subject: OffBeat question...Java performance.
> >
> > > Hi,
> > >
> > > I am trying to judge the performance impact of the following Java
code.
> > >
> > >         String [] arrayStr = new String[20000];
> > >         System.out.println(System.currentTimeMillis());
> > >         for(i=0;i<arrayStr.length;i++){
> > >                     String a="aa";
> > >         }
> > >         System.out.println(System.currentTimeMillis());
> > >
> > > Output:
> > > 1008319728796
> > > 1008319728799
> > >
> > >         String [] arrayStr = new String[20000];
> > >         int length = arrayStr.length;
> > >         System.out.println(System.currentTimeMillis());
> > >         for(i=0;i<arrayStr.length;i++){
> > >             String a="aa";
> > >         }
> > >         System.out.println(System.currentTimeMillis());
> > >
> > > Output:
> > > 1008319767200
> > > 1008319767221
> > >
> > > In my view the first code stub should have been faster as in the
second
> > > snippet we are getting an overhead of a instance variable call over an
> > > String [] object compared to the length already computed in the first
> > > one. What is happening behind the scene, I am not aware. Could
somebody
> > > please explain.
> > >
> > > Thanks,
> > > -ShriKant
> > >
> > >
> >
>
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