If you ever want to know how your algorithm became to be, try inserting some
System.out.printlnalgorithmcalculations);
or
out.printlnalgorithmcalculations);
Then you will see how the values added etc~
----- Original Message -----
From: "Miao, Franco CAWS:EX" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Sunday, January 06, 2002 2:30 AM
Subject: A Java question
> 1. public class TeSet {
> 2. public static void main(String args[]) {
> 3. int m = 2;
> 4. int p = 1;
> 5. int t = 0;
> 6. for(;p < 5;p++) {
> 7. if(t++ > m) {
> 8. m = p + t;
> 9. }
> 10. }
> 11. System.out.println("t equals " + t);
> 12. }
> 13. }
>
>
> Compile and run it, t=4. Don't know why?
>
> Can anyone give me some clue how it is caculated, thanks!
>
> Franco
>
>
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