ama ne razbrah zashto da gi preobrazuvash do string?
public boolean equals(byte[] b1, byte[] b2) {
  if( b1.length != b2.length ) {
    return false;
  } else {
    for(int i=0;i<b1.length;i++) {
      if( b1[i] != b2[i]) return false;
    }
    return true;
  }
}
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ProSyst Bulgaria Ltd.            Valentin Valchev
48 Vladajska Str.                Project Manager
Sofia 1606, Bulgaria             Dept: mBedded Server/Broadband
http://www.prosyst.com/          Phone: +359 02 (9631394) 223
---------------------------------------------------------------
Leading Software Technology for Open Service Gateways
----- Original Message -----
Sent: Wednesday, December 05, 2001 12:37 PM
Subject: [jug-bg] Sravnjavane na masivi ot bajtove

        Zdravejte,
    Verojatno vuprosut mi ima mnogo elementaren
otgovor, no mozhe li njakoj da mi predlozhi
po-optimalen variant za sravnenie na dva masiva ot
bajtove osven preobrazuvaneto na masivite do stringove
i posle sravnjavane po leksikografski metod. Trjabva
da se ima predvid, che masivite mozhe i da ne sa s
ednakva dulzhina.
     Blagodarja predvaritelno i ne mi se smejte
mnogo:))))
                              Pozdrav: Teodor

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