On my system, the two functions produce different LLVM IR:

julia> code_llvm(f1, ())

define i64 @julia_f115727() {
top:
  %0 = call i64 @julia_power_by_squaring1373(i64 10, i64 8), !dbg !726
  %1 = icmp slt i64 %0, 1, !dbg !726
  br i1 %1, label %L2, label %if, !dbg !726

if:                                               ; preds = %top, %if
  %j.04 = phi i64 [ %3, %if ], [ 1, %top ]
  %k.03 = phi i64 [ %4, %if ], [ 1, %top ]
  %2 = and i64 %k.03, 1, !dbg !727
  %3 = add i64 %j.04, %2, !dbg !727
  %4 = add i64 %k.03, 1, !dbg !728
  %5 = call i64 @julia_power_by_squaring1373(i64 10, i64 8), !dbg !726
  %6 = icmp sgt i64 %4, %5, !dbg !726
  br i1 %6, label %L2, label %if, !dbg !726

L2:                                               ; preds = %if, %top
  %j.0.lcssa = phi i64 [ 1, %top ], [ %3, %if ]
  ret i64 %j.0.lcssa, !dbg !729
}

julia> code_llvm(f2, ())

define i64 @julia_f215728() {
top:
  %0 = call i64 @julia_power_by_squaring1373(i64 10, i64 8), !dbg !729
  %1 = icmp slt i64 %0, 1, !dbg !729
  br i1 %1, label %L6, label %L3, !dbg !729

L3:                                               ; preds = %top, %L3
  %j.08 = phi i64 [ %3, %L3 ], [ 1, %top ]
  %k.07 = phi i64 [ %4, %L3 ], [ 1, %top ]
  %2 = and i64 %k.07, 1, !dbg !730
  %3 = add i64 %j.08, %2, !dbg !730
  %4 = add i64 %k.07, 1, !dbg !731
  %5 = call i64 @julia_power_by_squaring1373(i64 10, i64 8), !dbg !729
  %6 = icmp slt i64 %5, %4, !dbg !729
  br i1 %6, label %L6, label %L3, !dbg !729

L6:                                               ; preds = %L3, %top
  %j.0.lcssa = phi i64 [ 1, %top ], [ %3, %L3 ]
  ret i64 %j.0.lcssa, !dbg !732
}

But the performance is identical or slightly in favor of f1.

 -- John

On Mar 28, 2014, at 8:02 AM, Stefan Karpinski <ste...@karpinski.org> wrote:

> Both way of writing a while loop should be the same. If you're seeing a 
> difference, something else is going on. I'm not able to reproduce this:
> 
> function f1()
>   j = k = 1
>   while k <= 10^8
>     j += k & 1
>     k += 1
>   end
>   return j
> end
> 
> function f2()
>   j = k = 1
>   while true
>     k <= 10^8 || break
>     j += k & 1
>     k += 1
>   end
>   return j
> end
> 
> function f3()
>   j = k = 1
>   while true
>     k > 10^8 && break
>     j += k & 1
>     k += 1
>   end
>   return j
> end
> 
> julia> @time f1()
> elapsed time: 0.644661304 seconds (64 bytes allocated)
> 50000001
> 
> julia> @time f2()
> elapsed time: 0.640951585 seconds (64 bytes allocated)
> 50000001
> 
> julia> @time f3()
> elapsed time: 0.639177183 seconds (64 bytes allocated)
> 50000001
> 
> All three functions produce identical native code. Can you send exactly what 
> your function definitions are, how you're timing them and perhaps the output 
> of code_native(f1,())?
> 
> 
> On Fri, Mar 28, 2014 at 10:48 AM, Laszlo Hars <laszloh...@gmail.com> wrote:
> Thanks, John, for your replies. In my system your code gives reliable 
> results, too, if we increase the loop limits to 10^9:
> 
> julia> mean(t1s ./ t2s)
> 11.924373323658703
> 
> This 12% makes a significant difference in my function of nested loops (could 
> add up to a factor of 2 slow down). So, the question remains:
> 
> - what is the fastest coding of a while loop?
> 

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