the `names` function is indeed the right way to go about it:
julia> un = Union(Int, Float64)
Union(Int64,Float64)
julia> names(un)
1-element Array{Symbol,1}:
:types
julia> un.types
(Int64,Float64)
julia> un.types[1]
Int64
julia> un.types[2]
Float64
For datatypes:
julia> type A
a::Int
b::Float64
end
julia> names(DataType)
14-element Array{Symbol,1}:
:fptr
:env
:code
:name
:super
:parameters
:names
:types
:ctor_factory
:instance
:size
:abstract
:mutable
:pointerfree
julia> A.types
(Int64,Float64)
Also have a look at this excellent post:
http://blog.leahhanson.us/julia-helps.html
On Fri, 2014-05-16 at 08:09, tony.hf.f...@gmail.com wrote:
> Hello, new user and subscriber here. Is there a way to decompose a
> UnionType back into its constituent type(s)?
>
> I tried names():
>
>> dt = Union(Int,Float64)
>> names(dt)
> 1-element Array{Symbol,1}:
> :types
>
> convert() seems to hit dead-ends.
>
> Help appreciated.
>
> Tony
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