Julia has repmat. You can look up its methods like this:
julia> methods(repmat)
# 3 methods for generic function "repmat":
repmat(a::AbstractArray{T,1},m::Int64) at abstractarray.jl:964
repmat(a::Union(AbstractArray{T,2},AbstractArray{T,1}),m::Int64) at
abstractarray.jl:950
repmat(a::Union(AbstractArray{T,2},AbstractArray{T,1}),m::Int64,n::Int64)
at abstractarray.jl:950
>From these signatures, you can read off that Julia expects integers as the
trailing arguments, not an array. The third signature is the one we're
looking for.
julia> A = rand(3, 3)
3x3 Array{Float64,2}:
0.595856 0.413262 0.652419
0.111673 0.709227 0.16245
0.577607 0.0896444 0.943816
julia> B = repmat(A, 1, 4)
3x12 Array{Float64,2}:
0.595856 0.413262 0.652419 0.595856 … 0.595856 0.413262 0.652419
0.111673 0.709227 0.16245 0.111673 0.111673 0.709227 0.16245
0.577607 0.0896444 0.943816 0.577607 0.577607 0.0896444 0.943816
Alternatively, you can use the splat operator, "..."
julia> B = repmat(A, [1, 4]...)
3x12 Array{Float64,2}:
0.595856 0.413262 0.652419 0.595856 … 0.595856 0.413262 0.652419
0.111673 0.709227 0.16245 0.111673 0.111673 0.709227 0.16245
0.577607 0.0896444 0.943816 0.577607 0.577607 0.0896444 0.943816
On Friday, May 16, 2014 11:18:14 AM UTC-7, paul analyst wrote:
>
> in matlab :
> x=[1,4]
> B=repmat(A,x)
>
> /(B==AAAA)
>
>
> how to replicate A in Julia
> Paul
>
>
>
