Yeah, this is definitely not how Julia works. Why not write a function that
does what you want, then call it on x_foo and then later on x_bar?
-- John
On Sep 7, 2014, at 4:34 PM, Alex <hollina...@gmail.com> wrote:
> Hi John,
>
> I don't actually want to generate variables like that, but perform actions on
> list of variables and I thought that example was a good way of boiling down
> the problem I was having. So what I'm really trying to do is something more
> like this. I guess I thought that ["foo", "bar"] was behaving like a macro
> list of things I want this action to be done on, which is apparently not the
> right way of thinking.
>
> n=5
> x_foo=zeros(n,n)
> x_bar=zeros(n,n)
>
> for i in ["foo","bar"]
>
> x_$i = x_$i + n
> println("x_$i")
>
> end
>
> x_foo
>
>
> On Sunday, September 7, 2014 3:07:10 PM UTC-7, John Myles White wrote:
> Hi Alex,
>
> You can’t use things like x_$i as variable names. The $i interpolation trick
> applies only to strings — no other construct in the entire language will
> perform this kind of interpolation.
>
> You could use a macro to generate variables like this, but it’s not clear to
> me why you’d want to. Why are you creating variables in a loop?
>
> Perhaps you’d prefer using a Dict instead?
>
> n = 5
> vars = Dict()
> for name in [“foo”, “bar”]
> vars[“x_$(name)”] = zeros(n, n)
> end
> vars[“x_bar”]
>
> — John
>
> On Sep 7, 2014, at 3:03 PM, Alex <holli...@gmail.com> wrote:
>
> > Hi Everyone,
> >
> > I've been having some trouble using a for loop to perform tasks over
> > similarly named vectors. This simple example below illustrates my problem
> > pretty well. I would like to create two 5x5 arrays of zeros, but with
> > dynamic names. In this case x_foo and x_bar would be the names. When I run
> > this code, it clearly is looping over the string set, but it is not
> > actually creating the array. I have had similar problem trying to call
> > arrays into functions dynamically based on their names. Clearly I am just
> > incorrectly referencing i, but I cannot figure it where the error is. I am
> > trying to port a complicated version of this code from Stata, where this is
> > quite easy to do by referencing i in your code as `i'. Sorry for such a
> > novice question, but this has been driving me nuts all day!
> >
> > Thanks in advance!
> >
> > Alex
> >
> > n=5
> > for i in ["foo","bar"]
> > x_$i=zeros(n,n)
> > println("x_$i")
> > end
> > x_bar
>
