Reading the code, there is also a `indent` option, i thought it accepted a
boolean, but not, I find it very unintuitive:
dump(io::IO, x, n::Int, indent) = xdump(dump, io, x, n, indent)
julia> dump(:(1 + 1 * 3 - 4^7), 10, false)
Expr
false head: Symbol call
false args: Array(Any,(3,))
false 1: Symbol -
false 2: Expr
false head: Symbol call
false args: Array(Any,(3,))
false 1: Symbol +
false 2: Int32 1
false 3: Expr
false head: Symbol call
false args: Array(Any,(3,))
false 1: Symbol *
false 2: Int32 1
false 3: Int32 3
false typ: Any
false typ: Any
false 3: Expr
false head: Symbol call
false args: Array(Any,(3,))
false 1: Symbol ^
false 2: Int32 4
false 3: Int32 7
false typ: Any
false typ: Any
And once can't use this argument, as a keyword argument:
julia> dump(:(1 + 1 * 3 - 4^7), indent="--->")
ERROR: function dump does not accept keyword arguments
Keyword arguments are slow? Or why are the not used that much throughout
the API?
El domingo, 4 de enero de 2015 09:53:35 UTC-6, Ismael VC escribió:
>
> julia> begin
> @show vara = 33
> @show varb = vara * 14
> @show varc = varb * 77
> end
> vara = 33 = 33
> varb = vara * 14 = 462
> varc = varb * 77 = 35574
> 35574
>
>
> On Sun, Jan 4, 2015 at 5:47 AM, Mike Innes <mike.j.in...@gmail.com> wrote:
>
>> Have you met @show?
>>
>> On 4 January 2015 at 11:10, <ele...@gmail.com> wrote:
>>
>>> I think you need a macro, something like:
>>>
>>> macro printvar(var)
>>> return :(print($(string(var))); print("="); println($var))
>>> end
>>>
>>> julia> a=2
>>> 2
>>>
>>> julia> @printvar a
>>> a=2
>>>
>>> Cheers
>>> Lex
>>>
>>> On Sunday, January 4, 2015 8:48:27 PM UTC+10, Arch Call wrote:
>>>>
>>>> I frequently find myself writing Julia snippet scripts like this:
>>>>
>>>>
>>>> vara = 33
>>>>
>>>> varb = vara * 14
>>>>
>>>> varc = varb * 77
>>>>
>>>> println(“varb = “, varb) #--debug print
>>>>
>>>> println(“varc = “, varc) #--debug print
>>>>
>>>>
>>>> I would like to eliminate having to enter the variable name twice
>>>>
>>>> in the debug print lines by using a function.
>>>>
>>>>
>>>> I have tried all kinds of variations of a debug print function like:
>>>>
>>>>
>>>> function debugprint(somevar)
>>>>
>>>> println(“???? = ”, somevar)
>>>>
>>>> end
>>>>
>>>>
>>>> What can I put in place of “????” to get the actual Symbol of the
>>>> variable being passed to debugprint?
>>>>
>>>
>>
>
