I'm hoping it wouldn't, but it is actually one of the things I would like to test.
On Wednesday, February 4, 2015 at 3:17:39 PM UTC+1, Michele Zaffalon wrote: > > Wouldn't the answer depend on the path you choose? > > On Wed, Feb 4, 2015 at 3:04 PM, Andrei Berceanu <andreib...@gmail.com > <javascript:>> wrote: > >> I guess what I'm trying to say is that your answer makes sense for >> continuous functions, while mine has jumps of 2\pi, and so the phase change >> is equal to the total number of these jumps (times 2\pi). Does this make >> sense? >> >> >> On Wednesday, February 4, 2015 at 11:36:51 AM UTC+1, Andrei Berceanu >> wrote: >>> >>> Sorry, perhaps I did not explain myself :) >>> One can see the phase oscillates between -\pi and \pi. >>> I would like to compute how many times the phase changes by 2\pi as one >>> goes around the origin. >>> >>> On Wednesday, February 4, 2015 at 1:31:53 AM UTC+1, Steven G. Johnson >>> wrote: >>>> >>>> >>>> >>>> On Tuesday, February 3, 2015 at 1:17:15 PM UTC-5, Andrei Berceanu wrote: >>>> >>>>> How can I numerically compute the total change in phase as one goes >>>>> around a closed loop centered on the site $m=n=0$? >>>>> >>>> >>>> Seems like >>>> >>>> totalchangeinphase(m,n) = 0 >>>> >>>> would work and be very efficient. (As you described your problem, >>>> your phase sounds like a single-valued function of m & n, hence the total >>>> change around any closed loop would be zero. Unless you mean something >>>> different by "total change"?) >>>> >>> >
