That is, julia> f(x::Int, y::Int=5, z::Int=3) = x+y+z f (generic function with 3 methods)
julia> f(x::Float64, args...) = f(floor(Int,x), args...) f (generic function with 4 methods) julia> f(5.0,1,2) 8 julia> f(5.0) 13 On Tuesday, July 21, 2015 at 7:53:01 AM UTC-7, Seth wrote: > > > > On Tuesday, July 21, 2015 at 7:14:02 AM UTC-7, Linus Härenstam-Nielsen > wrote: >> >> I am looking for a way to automatically pass on all keyword arguments >> through a function. Naively I would like to be able to do something like >> this: >> >> f(x::Int; y::Int=5, z::Int=3) = x+y+z >> f(x::Float64; args...) = f(floor(x), args...) >> >> But that doesn't work currently (actually, it causes StackOverflowError >> in 0.4.0). So far I've been using the following instead: >> >> f(x::Float64, y::Int=5, z::Int=3) = f(floor(x), y=y, z=z) >> >> But that gets messy very quickly if there are several keyword arguments >> to handle. Does anyone know of a clean way to do this? >> >> >> > I think you're getting the stack overflow because your call to floor > doesn't convert to Int, so f(x::Float64; args...) keeps getting called > recursively. What happens if you change your second method to > > f(x::Float64, y::Int=5, z::Int=3) = f(floor(Int, x), y=y, z=z) > > instead? > >
