It's also perfectly normal/valid to do the loop explicitly. Just use
Array(T, r, c) to allocate, or zeros(T, r, c) or fill(val,r,c) to allocate
and initialize.
On Tue, Sep 15, 2015 at 2:38 PM, Stefan Karpinski <ste...@karpinski.org>
wrote:
> You can use array comprehensions, e.g.:
>
> julia> f(x,y) = 2x + 3y - 1
> f (generic function with 1 method)
>
> julia> [f(x,y) for x=1:7, y=1:5]
> 7x5 Array{Int64,2}:
> 4 7 10 13 16
> 6 9 12 15 18
> 8 11 14 17 20
> 10 13 16 19 22
> 12 15 18 21 24
> 14 17 20 23 26
> 16 19 22 25 28
>
>
> On Tue, Sep 15, 2015 at 3:53 AM, Michael Borregaard <
> mkborrega...@gmail.com> wrote:
>
>> Hi,
>> I am trying to migrate from R to julia. I am trying to wrap my head
>> around:
>> In R, there are the apply functions - when used with, e.g. a function
>> that returns a 1d array of constant length, they will return a 2d array
>> with the results. In julia, using map() will return a Array{Array{T, 1}, 1}
>> . What is the best, ideomatic way of building an Array{T, 2} from repeated
>> runs of a function? A hcat() call at the end of a forloop? Initializing an
>> array with the right dimensions with zeros(T, r, c) an indexing inside a
>> for loop? Or is there something smarter/nicer/better?
>>
>> Thanks,
>> Michael
>>
>
>
