There may be a slicker way to do this, but this should work: julia> fngen(expr,fn) = eval(parse(string(fn)* "=" * string(expr))) fngen (generic function with 1 method)
julia> expr = :(x + y) :(x + y) julia> fngen(expr,:(f(x,y))) func (generic function with 1 method) julia> f(2,2) 4 On Thursday, October 22, 2015 at 11:10:09 AM UTC-5, Jānis Erdmanis wrote: > > I am implementing boundary element method with curved elements. As it is > daunting task to evaluate derivatives I thought about using `Calculus` > symbolic differentiation which as output gives expression. Now I need to > convert this expression to a function, but how can I do it? > > As an example consider > expr = :(x + y) > how can I convert it to the function? > function f(x,y) > # Some magic here > end > > >
