One relatively neat way to do this is mapreduce(exact,hcat,linspace(0,10,100))
On Wednesday, 28 October 2015 02:38:56 UTC+10, Gabriel Gellner wrote: > > Okay sorry tab seems to send ... > > I am trying my to figure out the Julian way to create a table of values > (matrix) from a function that returns multiple values. As this is really > thinking about the problem as a function that generates the rows of the > table it feels super awkward to do this in Julia currently. For example, > lets say I have a function of the form: > > function exact(t) > yout = zeros(2) > yout[1] = 3.0*exp(t) - 2.0*exp(t) > yout[2] = exp(t) + 2.0*exp(t) > yout > end > > then what i want is a matrix of these solutions so my first thought is to > do > > esol = [exact(t) for t in linspace(0, 10, 100)] > hcat(esol...)' > > is this the idiomatic solution? > > Is there a better way to do this? How do people generally deal with Array > or Arrays. Feels weird to me currently. > > Gabriel > > > On Tuesday, 27 October 2015 09:31:22 UTC-7, Gabriel Gellner wrote: >> >> I am trying my to figure out the Julian way to create a table of values >> (matrix) from a function that returns multiple values. As this is really >> thinking about the problem as a function that generates the rows of the >> table it feels super awkward to do this in Julia currently. For example, >> lets say I have a function of the form: >> >> function exact_solution(t) >> >>
