Hi everybody,
It looks like i found memory leak in a Task related code and fatal error.
First, please look at this example:
function leak()
for i=1:10000
f = eval(:(function() produce() end))
t = @async f()
consume(t)
# stop the Task
t.exception = null
try
yieldto(t)
end
end
gc()
end
Every time i run leak() function, memory usage of juia process increases on
~35mb on my machine.
Second issue (with fatal error) is with the same code, but one simple
change:
function leak()
for i=1:10000
f = eval(:(function() produce() end))
t = @async f()
#consume(t) # this is a change
# stop the Task
t.exception = null
try
yieldto(t)
end
end
gc()
end
This change produces an error like this:
fatal: error thrown and no exception handler available.
null
rec_backtrace at /usr/bin/../lib/x86_64-linux-gnu/julia/libjulia.so
(unknown line)
jl_throw at /usr/bin/../lib/x86_64-linux-gnu/julia/libjulia.so (unknown
line)
unknown function (ip: 0x7fc9e946f372)
yieldto at ./task.jl:71
jl_apply_generic at /usr/bin/../lib/x86_64-linux-gnu/julia/libjulia.so
(unknown line)
wait at ./task.jl:371
task_done_hook at task.jl:174
jl_apply_generic at /usr/bin/../lib/x86_64-linux-gnu/julia/libjulia.so
(unknown line)
unknown function (ip: 0x7fc9e946eb4a)
unknown function (ip: (nil))
And finally, it works fine (without memory leaks) with this small change:
function leak()
for i=1:100000 # added one zero symbol at the end
f = function() produce() end # removed eval()
t = @async f()
consume(t)
# stop the Task
t.exception = null
try
yieldto(t)
end
end
gc()
end
So, my question is: what i should change to prevent memory leaks?
Thanks
julia> versioninfo()
Julia Version 0.4.2
Commit bb73f34 (2015-12-06 21:47 UTC)
Platform Info:
System: Linux (x86_64-linux-gnu)
CPU: Intel(R) Core(TM) i7-4700HQ CPU @ 2.40GHz
WORD_SIZE: 64
BLAS: libopenblas (NO_LAPACK NO_LAPACKE DYNAMIC_ARCH NO_AFFINITY Haswell)
LAPACK: liblapack.so.3
LIBM: libopenlibm
LLVM: libLLVM-3.3
