I'm not quite sure if this is what you're asking, but if you want a scalar
function to work elementwise on an array, try `map`.
--Tim
On Wednesday, February 10, 2016 04:15:30 AM Ferran Mazzanti wrote:
> Thanks Mauro...
>
> using two methods was the first thing I thought, but I strongly dislike the
> idea because I'd have to maintain two different functions
> to do the same, which doubles the possibility of introducing bugs. I like
> the idea of keeping the main function simple and unique,
> so if I change something the changes apply to all calculations in the same
> way.
>
> Best regards,
>
> Ferran.
>
> On Wednesday, February 10, 2016 at 12:11:00 PM UTC+1, Mauro wrote:
> > Probably cleanest would be to make two methods, one for scalars, one for
> > arrays. For the array one just loop.
> >
> > This also works, but returns an array for scalar input (type inference
> > should work once wrapped in a function):
> >
> > julia> x = 5
> > 5
> >
> > julia> [ xi>5 ? 0:1 for xi in x]
> >
> > 1-element Array{Any,1}:
> > 1
> >
> > julia> x = 1:10
> > 1:10
> >
> > julia> [ xi>5 ? 0:blah for xi in x]
> >
> > 10-element Array{Any,1}:
> > 1
> > 1
> > 1
> > 1
> > 1
> > 0
> > 0
> > 0
> > 0
> > 0
> >
> > On Wed, 2016-02-10 at 11:58, Ferran Mazzanti <ferran....@gmail.com
> >
> > <javascript:>> wrote:
> > > Hi folks,
> > >
> > > probably a stupid question but can't find the answer, so please help if
> >
> > you
> >
> > > can :)
> > > I would like to evaluate a if.. else.. statement on a whole array.
> >
> > Actually
> >
> > > it's a bit more complicated, as I have a function that
> > > previously was
> > >
> > > function u2(x)
> > >
> > > return 0.5*(u2_0(x)+u2_0(Lbox-x))-u2_0(Lbox/2)
> > >
> > > end;
> > >
> > > for some other defined function u2(x) and constant L_box. The thing is
> >
> > that
> >
> > > I could directly evaluate that on a scalar x and on an array.
> > > Now I have to change it and check if x is smaller than Lbox/2, returning
> > > the same as above if it is, or 0 otherwise.
> > > I tried something of the form
> > >
> > > function u2(x)
> > >
> > > return x.>Lbox/2 ? 0 : 0.5*(u2_0(x)+u2_0(Lbox-x))-u2_0(Lbox/2)
> > >
> > > end;
> > >
> > > but that complains when x is an array. What would be the easiest way to
> > > achieve this? It should work for both scalars and arrays...
> > >
> > > Best regards and thanks,
> > >
> > > Ferran.
