+ 1 to Gabriel's reply.
On Tuesday, April 5, 2016 at 2:36:09 PM UTC+1, Gabriel Gellner wrote: > > you can do the python example as: > > a[[1, 4] + range(7, 17, 2)] > (ignoring the issues that this is not the same range as julia since python > uses 0-based indices ...) > > you don't need to index with an ndarray, and that way you can get the nice > use of the + operator for concatenate. > > Lacking the : for range does make some code more verbose, but you get used > to it. > > For the julia example isn't matlab like concatenation using ';' being > removed from julia? > > As to the overall topic I don't think it is fair to have to poo-poo python > to also feel that julia does it well. I really like both. Arguing about 0 > vs 1 based indexing is like emacs vs vi ... it leads to nothing but madness > ... > > R + matlab + julia + fortran + Mathematica use 1 based and the world > hasn't ended > > sometimes 0 based is nice, but you get used to not having it, just like > you get used to having it. > > As for the truncating integer div ... I do hate that that in python and do > "from __future__ import division" always ;) > > On Monday, April 4, 2016 at 11:55:40 PM UTC-7, DNF wrote: >> >> Typo, I meant to type: >> >> Python 3.5 >> a[i*len(a)//n:(i+1)*len(a)//n] >> >> Julia: >> a[1+i*end÷n:(i+1)end÷n] >> >> I'm just learning Python, and must say I find indexing in Python to be >> very awkward compared to Julia or Matlab. Do you have any suggestion for >> how I should do this in Python? >> a[[1; 4; 7:2:15]] >> So far I've got: >> a[np.concatenate(([1,4], np.arange(7,17,2)))] >> >> >> >> >> On Tuesday, April 5, 2016 at 8:46:57 AM UTC+2, DNF wrote: >>> >>> >>> On Saturday, April 2, 2016 at 1:55:55 PM UTC+2, Spiritus Pap wrote: >>>> >>>> A simple example why it makes my *life hard*: Assume there is an array >>>> of size 100, and i want to take the i_th portion of it out of n. This is a >>>> common scenario for research-code, at least for me and my friends. >>>> In python: >>>> a[i*100/n:(i+1)*100/n] >>>> In julia: >>>> a[1+div(i*100,n):div((i+1)*100,n)] >>>> >>>> A lot more cumbersome in julia, and it is annoying and unattractive. >>>> This is just a simple example. >>>> >>> >>> Python 3.5 >>> a[i*len(a)//n:(i+1)*len(a)//n] >>> >>> Julia: >>> a[1+i*end÷5:(i+1)end÷5] >>> >>>
