to replace with 42, maybe: map!((i) -> isnan(i)? 42 : i, a)
to delete: deleteat!(a, find(isnan, a)) On Thursday, April 7, 2016 at 2:33:56 PM UTC+2, jw3126 wrote: > > I have an array, which has some NaNs and I want to do things like replace > them by 42 or delete them. What is the canonical way to do this? >
