On Fri, Apr 29, 2016 at 8:33 AM, Tamas Papp <tkp...@gmail.com> wrote: > Default value expressions for optional and keywords arguments are > evaluated in the scope of the module that defines the function, which > seems to be the Right Thing to do, but I could not find this specified > in the manual. Did I miss it or is it just not spelled out? Asking > because I would submit a correction if it is the intended behavior. Eg
This is just the default lexical scope. Note that it is *not* the module that defines the function for closures. There's already a section about the scope of default arguments so it is fine if you want to submit something short that clarify this a little bit. > > --8<---------------cut here---------------start------------->8--- > module Foo > bar=1 > foo(a=bar)=a > end > > module Baz > import Foo.foo > bar=2 > foo2()=foo() > end > > Baz.foo2() # will then eval to 1 > --8<---------------cut here---------------end--------------->8--- > > Best, > > Tamas
