Am Montag, 16. Mai 2016 16:11:39 UTC+2 schrieb Chris Rackauckas:
>
> I make this function to solve this problem in one of m codes:
>
> function shapeResult(res)
>   #Input is a vector of tuples
>   #Output the "columns" as vectors
>   out = cell(length(res[1]))
>   for i = 1:length(res[1])
>     out[i] = Vector{typeof(res[1][i])}(length(res))
>   end
>   for i = 1:length(res), j = 1:length(out)
>     out[j][i] = res[i][j]
>   end
>   return tuple(out...)
> end
>
> Thanks, but it only works for a vector, not for a matrix as input. I could 
rewrite it for that. So there is no solution without for-loops?

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