If you are proposing that sum(p,1) should drop dimensions but sum(p,[1]) should not, I don't think there is an easy solution like that. What should sum(p,1:2) do?
On Friday, May 27, 2016 at 6:52:58 AM UTC-4, Christoph Ortner wrote: > > > > On Thursday, 26 May 2016 03:03:03 UTC+1, Tim Holy wrote: >> >> Since you asked...from my perspective, the easiest argument against it is >> >> pnormalized = p ./ sum(p, 1) >> >> If you drop the summed dimension, that won't work anymore. One can write >> >> pnormalized = p ./ reshape(sum(p, 1), 1, size(p, 2)) >> > > Would the point of the new notation be to write > > pnormalized = p ./ sum(p, [1]) > >
