Ah, right, I hadn't read your definition carefully.
A[[CartesianIndex(1,1), CartesianIndex(2,3)]] = [0,0]
Seems to be working correctly. So given your ind matrix, we can do
A[mapslices(s->CartesianIndex(s...), ind, 2)]
but I doubt that it'll be very performant. Could you directly output
CartesianIndex objects?
On Wed, Oct 26, 2016 at 4:11 PM, Tsur Herman <tsur.her...@gmail.com> wrote:
> julia> A=rand(4,4)
> 4×4 Array{Float64,2}:
> 0.427998 0.720987 0.375013 0.432887
> 0.0333443 0.602459 0.946685 0.817995
> 0.402635 0.571399 0.553542 0.0234215
> 0.707829 0.339795 0.451387 0.358248
>
>
> julia> ind = [1 1; 2 2; 3 3]
> 3×2 Array{Int64,2}:
> 1 1
> 2 2
> 3 3
>
>
> julia> A[ind]
> 3×2 Array{Float64,2}:
> 0.427998 0.427998
> 0.0333443 0.0333443
> 0.402635 0.402635
>
>
>
> julia>
>
> On Wednesday, October 26, 2016 at 6:19:45 PM UTC+3, Cedric St-Jean wrote:
>>
>> A[indices] = Values
>>
>> ?
>>
>> On Wednesday, October 26, 2016 at 9:53:17 AM UTC-4, Tsur Herman wrote:
>>>
>>> What would you suggest is a fast and elegant way to achieve indexing
>>> into an array using a set of indices?
>>>
>>> function setindices!(A,Values,Indices)
>>> assert(length(Values) == size(Indices,1))
>>> for i=1:length(Values)
>>> setindex!(A,Values[i],(Indices[i,:]...)...)
>>> end
>>> end
>>>
>>> I am currently using this function and I was wondering whether I missed
>>> something.
>>>
>>>
