a = Vector{String}
is also a good option.
On Monday, November 7, 2016 at 5:27:49 PM UTC+2, Steven G. Johnson wrote:
>
>
>
> On Monday, November 7, 2016 at 9:45:37 AM UTC-5, Mauro wrote:
>>
>> On Mon, 2016-11-07 at 15:27, Fred <fred.so...@gmail.com> wrote:
>> > Hi Steven,
>> >
>> >
>> > I also tried a = Array{String}() unfortunately it produces errors as
>> well.
>>
>> Array{String}(0)
>>
>
> Whoops, sorry about the typo.
>
