https://bugs.kde.org/show_bug.cgi?id=489660
--- Comment #8 from Gabriel Barrantes <gabriel.barrantes....@outlook.com> --- it leads to issues, for example: if you are in hex mode and enter 10+1 result is 11 hex (17 decimal) and then change to binary, what should be done? I am thinking on these 2 possibilities: 1. interpret the input as binary-> new result = 11 bin (3 decimal) 2. add a 0x to the input, 0x10+0x1 same result but change it to binary, so result = 10001 however if the input is 1A (hex mode) and then mode is changed to binary: 1. can't be done, so it throws input error since 1A is not a valid entry for the binary mode 2. is a decent choice as I said that would keep the entry valid... Currently is doing 1 in all cases. 2 is probably better but requires some development in the component... -- You are receiving this mail because: You are watching all bug changes.