On Thu, 23 Mar 2000, you wrote:
> The mkboot shell script uses the dd command twice:
>
> dd if=stage1 of=/dev/fd0 bs=512 count=1
> dd if=stage2 of=/dev/fd0 bs=512 seek=1
>
> Please let me know if I understand the purpose of dd correctly. The block
> size is 512 bytes because bs=512. Line 1 writes out exactly one block of
> stage1. Line 2 skips ahead 1 block in /dev/fd0 and writes out the rest of
> stage2.
>
> Alternative 1.
> Doesn't this do the same thing?
>
> dd if=stage1 of=grub-boot bs=512 count=1
> dd if=stage2 of=grub-boot bs=512 seek=1
> cat grub-boot > /dev/fd0
>
> Alternative 2.
> If stage1 is exactly 512 bytes, doesn't this do the same thing?
>
> cat stage1 + stage2 > /def/fd0
>
Both the alternatives seem to be right. I'll try them....
-Corrado
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