Hello. Could anybody help with kexec. I cannot find some informaton from google. I try to use kexec for fast boot new kernel but I have error below:
# kexec -l /boot/vmlinuz-3.12.0-rc1+ --initrd=/boot/initramfs-3.12.0-rc1+.img --command-line="$(cat /proc/cmdline)" kexec_load failed: Operation not permitted entry = 0x24eff5790 flags = 3e0000 nr_segments = 3 segment[0].buf = 0x7fd169783210 segment[0].bufsz = 505250 segment[0].mem = 0x24d000000 segment[0].memsz = 1413000 segment[1].buf = 0xbc3770 segment[1].bufsz = 4310 segment[1].mem = 0x24efef000 segment[1].memsz = 5000 segment[2].buf = 0xbba650 segment[2].bufsz = 90e0 segment[2].mem = 0x24eff5000 segment[2].memsz = b000 KEXEC option in the config is enabled. How can I decid this problem? Regards, Dmitry
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