Hi
Okay��I think I realy understand this problem. The point I think is all free objects are linked by index number, the first one's index is stored in slabp->free, and the first one's object descriptor stores the next one's index, and so on!
You finally get the picture :)
regards, Mulyadi -- To unsubscribe from this list: send an email with "unsubscribe kernelnewbies" to [EMAIL PROTECTED] Please read the FAQ at http://kernelnewbies.org/FAQ
